An inelastic ball falls from a height of `100` metres. It loses `20%`

1.	An inelastic ball falls from a height of `100` metres. It loses `20%` of its total energy due to impact. The ball will now rise to a height ofA. 80 mB. 40 mC. 60 mD. 20 m
Answer» Correct Answer - A 20% energy is lost that means 80% still remains so by that 80% mgh the mass is not given assume to be 1 kg 80/100mgh = 0 therefore h =100mg/80 Correct option (A) 80 m Percentage loss of total energy = \(\frac{h_1-h_2}{h_1}\times100\) 20 = \((\frac{100-h_2}{100})\times100\) 20 = (100 - h₂) h₂ = 100 - 20 h₂ = 80 m

An inelastic ball falls from a height of `100` metres. It loses `20%` of its total energy due to impact. The ball will now rise to a height ofA. 80 mB. 40 mC. 60 mD. 20 m

Answer» Correct Answer - A

20% energy is lost that means 80% still remains so by that

80% mgh

the mass is not given assume to be 1 kg

80/100mgh = 0

therefore

h =100mg/80

Correct option (A) 80 m

Percentage loss of total energy = \(\frac{h_1-h_2}{h_1}\times100\)

20 = \((\frac{100-h_2}{100})\times100\)

20 = (100 - h₂)

h₂ = 100 - 20

h₂ = 80 m

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An inelastic ball falls from a height of `100` metres. It loses `20%` of its total energy due to impact. The ball will now rise to a height ofA. 80 mB. 40 mC. 60 mD. 20 m

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