An infinite line of charge `lamda` per unit length is placed along the y-axis. The work done in moving a charge q from `A(a,0)` to `B (2a,0)` isA. `(q lamda)/(2piepsilon_0) `"ln" 2`B. `(qlamda)/(2piepsilon_0)"ln" (1/2)`C. `(qlamda)/4piepsilon_0) "ln" sqrt2`D. `(qlamda)/(4piepsilon_0) "ln"2`

An infinite line of charge `lamda` per unit length is placed along the

1.	An infinite line of charge `lamda` per unit length is placed along the y-axis. The work done in moving a charge q from `A(a,0)` to `B (2a,0)` isA. `(q lamda)/(2piepsilon_0) `"ln" 2`B. `(qlamda)/(2piepsilon_0)"ln" (1/2)`C. `(qlamda)/4piepsilon_0) "ln" sqrt2`D. `(qlamda)/(4piepsilon_0) "ln"2`
Answer» Correct Answer - B `W_(ArarrB)=q(V_B-V_A)` `=q[-int_A^BEdr]=q int_B^A Edr` `=q int_(2a)^a lamda/(2piepsilon_0)dr= (qlamda)/(2piepsilon_0) "in" (1/2)`

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An infinite line of charge `lamda` per unit length is placed along the y-axis. The work done in moving a charge q from `A(a,0)` to `B (2a,0)` isA. `(q lamda)/(2piepsilon_0) `"ln" 2`B. `(qlamda)/(2piepsilon_0)"ln" (1/2)`C. `(qlamda)/4piepsilon_0) "ln" sqrt2`D. `(qlamda)/(4piepsilon_0) "ln"2`

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