An infinitely long conductor PQR is bent to form a right angle as show

1.	An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field strength due to this current at the point M is H1. Now, another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field strength at M is now H2. The ratio H1/H2 is given by(a) 1/2 (b) 1 (c) 2/3 (d) 2
Answer» Correct Answer is: (c) 2/3 The magnetic field strength at M due to QR is zero in all cases. When QS carries I/2 current, the field strength at M due to QS is H₁/2. Then H₂ = H₁ + H₁/2 = 3H₁/2 or H₁/H₂ = 2/3.

An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field strength due to this current at the point M is H1. Now, another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field strength at M is now H2. The ratio H1/H2 is given by(a) 1/2 (b) 1 (c) 2/3 (d) 2

Answer»

Correct Answer is: (c) 2/3

The magnetic field strength at M due to QR is zero in all cases.

When QS carries I/2 current, the field strength at M due to QS is H₁/2. Then

H₂ = H₁ + H₁/2 = 3H₁/2

or H₁/H₂ = 2/3.

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