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An infinity long cylinder of radius R has an infinitely long cylindrical cavity of radius `(R)/(2)` are shown in the figure. The remaining portion has uniform volume charge density `rho`. The magnitude of electrical field at the centre of the cavity is-A. `(rhoR)/(6epsilon_(0))`B. `(rhoR)/(4epsilon_(0))`C. `(rhoR)/(2epsilon_(0))`D. `(rhoR)/(3epsilon_(0))` |
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Answer» Correct Answer - B Electric field in cavity is given as `=(rhor)/(2epsilon_(0))` where `r` is distance between the axis of cylinder cavity so, E in cavity `=(rho(R)/(2))/(2epsilon_(0))=(rhoR)/(4epsilon_(0))` |
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