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An insecticide has the following percentage composition by mass. 47.5 % C, 2.54 % H and 50.0% Cl. Determine its empirical formula and molecular formulae. Molar mass of the substance is 354.5 gmol^(-1) |
Answer» Solution :![]() `:.` The EMPIRICAL FORMULA is `C_(14)H_(9)Cl_(5)` Calculation of MOLECULAR formula: The empirical formula MASS `(C_(14)H_(9)Cl_(5))=(14xx12)+(9xx1)+(5xx35.5)` 168+9+177.5=354.5 n = `("Molecular mass")/("Empirical formula mass")=354.5/354.5=1` Molecular formula=`("Empirical formula")_(n)` = `(C_(14)H_(9)Cl_(5))` `:.` Molecular formula = `C_(14)H_(9)Cl_(5)` |
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