An insulated container containingmonoatomic gas of molar mass m is moving with a velocity V_(0). If the container is suddenly stopped , find the change in temperature .

An insulated container containingmonoatomic gas of molar mass m is mov

1.	An insulated container containingmonoatomic gas of molar mass m is moving with a velocity V_(0). If the container is suddenly stopped , find the change in temperature .
Answer» `(mv_(0)^(2))/(2R)` `(mv_(0)^(2))/(3R)` `(3mv_(0)^(2))/(2R)` `(1)/(2)(mv_(0)^(2))/(R)` Solution :Here, M= mole mass of the gas `v_(o)` = initial speed Mass of gas = n m (n= number of moles in the gas) `therefore` Initial KINETIC energy of the gas `=1/2(nm)v^(2)` FINAL KE of gas = 0 Change in Kinetic energt, `DeltaK=1/2(nm)v^(2)` Let change in temperature of gas = `DELTAT` Change in internal energy of the gas `DeltaU=nC_(v)DeltaT=n((3)/(2)R)DeltaT` As, `DeltaU=DeltaK` `implies3/2nRDeltaT=1/2mnv_(o)^(2)` `impliesDeltaT=(mv_(0)^(2))/(3R)`