Saved Bookmarks
| 1. |
An insulated container monoatomic gas of molar mass m is moving with a velocity nu_(0). If the container is suddenly stopped. Find the change in temperature. |
|
Answer» SOLUTION :Suppose the container has N moles of the monoatomic gas. Then the loss in K.E. of the gas `DeltaE=1/2(mn)nu_(O)^(2)` If the TEMPERATURE of the gas change by `DeltaT,` then heat gained by the gas, `DeltaQ=nC_(V)DeltaT` `DeltaQ=3/2 nRDeltaT` Now, DeltaQ=DeltaE `3/2nDeltaT=1/2(mn)nu_(O)^(2)` `DeltaT=(mnu_(O)^(2))/(3R)` |
|