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An integrating factor of the differential equation ` x(dy)/(dx) +y log x = xe^(x)x^((-1)/2log x), (x gt 0 ), ` isA. `x^(logx)`B. ` (sqrt(x))^(logx)`C. ` (sqrt(e))^((logx)^(2))`D. ` e^(x^(2))` |
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Answer» Correct Answer - c Given differential equation is ` x(dy)/(dx) + y log x = xe^(x) x ^((-1//2)logx)` ` (dy)/(dx) + y. 1/x log x = e^(x) x ^((-1//2))logx` Here , ` P = 1/x log x and Q = e^(x)x^((-1//2)logx)` ` :. IF = e ^(int 1/xlogxdx) = e^((logx)^(2)/2)=(sqrt(e))^((logx)^(2))` |
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