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An iodine molecule dissociates into atom after absorbinglight of wavelength 4500Å. If quantum of radiation isabsorbedby eachmolecule calculate thekineticenergyof iodine (Bond energy of I_(2) is 240 kJ mol^(-1))

Answer»

Solution :Bond ENERGY PER molecule of `I_(2)= (240 xx 1000)/(6.022 xx 10^(23))J= 3.984 xx 10^(-19)J`
Energy absorbed `=(hc)/(lamda)`
`=(6.626 xx 10^(-34) xx 3 xx 10^(8))/(4500 xx 10^(10))= 4.417 xx 10^(-19)J`
`THEREFORE` KE of ONE `I_(2)` molecule `=4.417 xx 10^(-19)- 3.984 xx 10^(-19)J = 4.33 xx 10^(-20)J`
KE of one I atom `=(4.33 xx 10^(-20))/(2)= 2.165 xx 10^(-20)J`


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