1.

An ion Mn^(3+) at has the magnetic moment equal to 4.9 BM. What is the value of a ?

Answer»


Solution :`therefore ` Magnetic moment =`sqrt(n(n+2)) = 4.9 B.M.`
`therefore ` n= 4 (where n is no. of unpaired ELECTRON)
THUS `Mn^(a+)` ioin has FOUR unpaired electron,`""_(25)Mn^(3+) : 1 s^2 2s^2 2p^6 3s^2 3p^6 3d^4 therefore a = 3`


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