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An ion with mass number 37 posseses one unit of negative charge. If the ion contains 11.1 % more neutrons than the electrons, find the symbol of the ion |
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Answer» SOLUTION :Suppose number of electrons in the ion = x Then number of neutrons `= x + (11.1)/(100) x = 1.111x` No. of electrons in the neutral ATOM `= x - 1 :.` No. of PROTONS `= x -1` Mass number = No. of neutrons + No. of protons `:. 37 = 1.111 x + x -1 or 2.111x = 38 or x = 18` `:.` No. of protons = Atomic no. `=x -1 = 18 - 1 = 17` Hence, the symbol of the ion will be `._(17)^(37)CL^(-1)` |
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