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An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, write its symbol. |
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Answer» Solution :As the ion carries one unit of negative charge, it will have onelectron more than the number of protons Let the number of ELECTRONS `= x` Number of protons `=x-1` Number of NEUTRONS `=x+(x xx11.1)/(100)=x+0.111x=1.111x` Solving for the value of x, `"rotons "+ "neutrons "=" MASS number "` `x-1=1.111x=37""x=(38)/(2.111)=18` Number oflectrons = 18 Number of protons `= 18 - 1 = 17` Number of neutrons `= 37-17 = 20` The ion under discussion is chloride and its SYMBOL is `Cl^(-)` |
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