1.

An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, write its symbol.

Answer»

Solution :As the ion carries one unit of negative charge, it will have onelectron more than the number of protons
Let the number of ELECTRONS `= x`
Number of protons `=x-1`
Number of NEUTRONS `=x+(x xx11.1)/(100)=x+0.111x=1.111x`
Solving for the value of x,
`"rotons "+ "neutrons "=" MASS number "`
`x-1=1.111x=37""x=(38)/(2.111)=18`
Number oflectrons = 18
Number of protons `= 18 - 1 = 17`
Number of neutrons `= 37-17 = 20`
The ion under discussion is chloride and its SYMBOL is `Cl^(-)`


Discussion

No Comment Found