1.

An ion with mass number 37 possesses unit negative charge.If the ion contains 11.1% more neutrons than electrons.Find the symbol of the ion.

Answer»

Solution :Let the number of electrons in an ion=x
`therefore `Number of neutrons `=n=x+(11.1)/(100)EV`
`=1.111x`
(As the number of neutrons are 11.1% more than the number of electrons)
In the neutral of atom,number of ELECTRON.
`e^(-)=x-1`(As the ICON carries-1 charge)
Similarly number of protons=P=x-1
Number of protons + number or neutrons=mass number =37
`:.(x-1)+1.111x=37`
2.111x=38
2.111x=38
`x=(38)/(2.111)=18.009=18`
`therefore`Number of protons =atomic number-1
=18-1=17
`therefore`the Number symbol of the icon`=UNDERSET(37)OVERSET(17)( Cl)^(-)`


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