Saved Bookmarks
| 1. |
An ion with mass number 37 possesses unit negative charge.If the ion contains 11.1% more neutrons than electrons.Find the symbol of the ion. |
|
Answer» Solution :Let the number of electrons in an ion=x `therefore `Number of neutrons `=n=x+(11.1)/(100)EV` `=1.111x` (As the number of neutrons are 11.1% more than the number of electrons) In the neutral of atom,number of ELECTRON. `e^(-)=x-1`(As the ICON carries-1 charge) Similarly number of protons=P=x-1 Number of protons + number or neutrons=mass number =37 `:.(x-1)+1.111x=37` 2.111x=38 2.111x=38 `x=(38)/(2.111)=18.009=18` `therefore`Number of protons =atomic number-1 =18-1=17 `therefore`the Number symbol of the icon`=UNDERSET(37)OVERSET(17)( Cl)^(-)` |
|