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An ion with mass number 37 prossesses unit negative charg. If contains 11.1% more neutrons than electrons. Find the symbol of the ion. |
Answer» Solution : Given that, `y =x + 11.1% of x` `= (x + (11.1)/(100)x) = x + 0.111 x` `y = 1.111 x` mass number = 37 number of protons + number of neutrons = 37 `(x - 1) + 1.111 x = 37` `x + 1.111x = 38` `2.111x = 38` `x = (38)/(2.11) = 18.900` `x = 18` (whole number) `:. "ATOMIC number" = x - 1` `= 18 - 1 = 17` Mass number = 37 SYMBOL of the ion `._(17)^(37)Cl^(-)`. |
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