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An ion with mass number `56` contains `3` units of positive charge and `30.4%` more neutrons then electrons. Assign the symbol to this ion. |
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Answer» Suppose number of electrons in the ion, `M^(3+)=x` `:.` Number of neutrons `=x+30.4/100x=1.304x` Number of electrons in the neutral atom `=x+3` `:.` Number of protons `=x+3` Mass number=Number of protons+Number of neutrons `56=x+3+1.304x` or `2.304x=53` or `x=23` `:.` Number of protons=Atomic no. `=x+3=23+3=26` Hence, the symbol of the ion will be `._(26)^(56)Fe^(3+)`. |
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