1.

An ionic solid `A^(o+)B^(Θ)` crystallizes as an bcc structure. The distance between cation and anion in the lattice is `338 pm`. The edge length of cell isA. `390.3` pmB. `100` pmC. `190.3` pmD. `195.15` pm

Answer» Correct Answer - A
In a body centred cubic unit cell, the distance between the cation and anion `(r_(+)+r_(-))` is related to the edge length (a) by
`r^(+)+r^(-)=sqrt(3)xx(a)/(2)therefore a=(2)/sqrt(3)(r^(+)+r^(-))7`
It is given that `(r^(+)+r^(-))` =338 pm
`therefore a=(2)/sqrt(3)xx338`pm
`thereforea=(2)/sqrt(3)xx338` pm `=(676)/(1.732)=390.3`pm


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