An iron ball and a feather are both falling from a height of 10 m. (a) What are the time taken by the iron ball and feather to reach the ground? (b) What are the velocities of iron ball and feather when they reach the ground? (Ignore air resistance and take g=10ms^(-2)

An iron ball and a feather are both falling from a height of 10 m. (a

1.	An iron ball and a feather are both falling from a height of 10 m. (a) What are the time taken by the iron ball and feather to reach the ground? (b) What are the velocities of iron ball and feather when they reach the ground? (Ignore air resistance and take g=10ms^(-2)
Answer» Solution :SINCE kinematic equations are independent of mass of the object, according to equation the time TAKEN by both iron ball and feather to REACH the ground are the same. This is given by `T=sqrt((2h)/(g))=sqrt((2xx10)/(10))=sqrt2s =1.414s` THUS, both feather and iron ball reach ground at the same time. By FOLLOWING equation both iron ball and feather reach the Earth with the same speed. It is given by `v=sqrt(2gh)=sqrt(2xx10xx10)=sqrt200ms^(-1)~~14.14ms^(-1)`