An iron ball has a diameter of `6 cm` and is `0.010 mm` too large to pass through a hole in a brass plate when the ball and plate are at a temperature of `30^@ C`. At what temperature, the same for ball and plate, will the ball just pass through the hole? Take the values of (prop) from Table `20 .2`.

An iron ball has a diameter of `6 cm` and is `0.010 mm` too large to p

1.	An iron ball has a diameter of `6 cm` and is `0.010 mm` too large to pass through a hole in a brass plate when the ball and plate are at a temperature of `30^@ C`. At what temperature, the same for ball and plate, will the ball just pass through the hole? Take the values of (prop) from Table `20 .2`.
Answer» Correct Answer - C `Delta d = d(alpha_B - alpha_(Fe)) Delta theta` :. `Delta theta = (Delta d)/(d(alpha _B -alpha_(Fe))` = `(0.01)/(60 xx 0.8 xx 10^-5)= 20.83^@ C` `:.` New temperature `= (30 + 20.83) = 50.83^@ C`

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