An iron ball has an air space in it, the ball weights ong kg in air and O-6 kg in water. Find the volume of the air space. Density of iron is 7200 kg m ^(-3).

An iron ball has an air space in it, the ball weights ong kg in air an

1.	An iron ball has an air space in it, the ball weights ong kg in air and O-6 kg in water. Find the volume of the air space. Density of iron is 7200 kg m ^(-3).
Answer» Solution :Volume of AIR space = (Volume of iron ball with air sapce- Volume of iron alone ) Loss of weight of ball = ` W_("air") - W_("WATER") ` `""=1-0.6 = 0..4 kg f ` Loss of weight of ball = weight of water displaced ` "" 0.4 ( kg f )= V xx d (kg f )` where ` "" d- ` DENSITY of water Volume of iron ball with air space = `V = (0.4 )/(1000)= 0.4 xx 10 ^(-3)m^(-3)` Volume or iron alone = ` ("mass")/( " density")` ` ""=(1)/( 7200)= 0.138 xx 10 ^(-3) m^(3)` ` therefore "" ` Volume of air space =(Volume of iron ball with air space -Volume of iron alone) ` ""= 0.4 xx 10^(-3)- 0.138 xx 10 ^(-3)` ` "" = 0.262 xx 10 ^(-3)m^(3)`