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An iron ball of diameter 6cm and is 0.01 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of 20^(@)C. The temperature at which (both for ball and plate) the ball just pass through the hole is (alpha_("iron")=12xx10^(-6)//1^(@)C,alpha_("brass")=18xx10^(-6)//1^(@)C) |
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Answer» `68^(@)C` |
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