An iron bar of length `10 cm` and diameter `2 cm` is placed in a magnetic field of intensity `1000Am^(-1)` With its length parallel to the direction of the field. Determine the magnetic moment produced in the bar if permeability of its material is `6.3xx10^(-4) TmA(-1)`.

An iron bar of length `10 cm` and diameter `2 cm` is placed in a magne

1.	An iron bar of length `10 cm` and diameter `2 cm` is placed in a magnetic field of intensity `1000Am^(-1)` With its length parallel to the direction of the field. Determine the magnetic moment produced in the bar if permeability of its material is `6.3xx10^(-4) TmA(-1)`.
Answer» we know that, `mu=mu_(0)(1+chi)` `rArr chi=(mu)/(mu_(0))-1=(6.3xx10^(-4))/(4pixx10^(-7))-1=500.6` Intensity of magnetisation, `I=chiH=500.6xx1000=5xx10^(5) Am^(-1)` `there` magnetic moment, `M=IxxV=Ixxpir^(2)l` `=5xx10^(5)xx3.14xx(10^(-2))^(2)xx(10xx10^(-2))=17.70A-m^(2)`

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An iron bar of length `10 cm` and diameter `2 cm` is placed in a magnetic field of intensity `1000Am^(-1)` With its length parallel to the direction of the field. Determine the magnetic moment produced in the bar if permeability of its material is `6.3xx10^(-4) TmA(-1)`.

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