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An iron rod is subjected to cycles of magnetisation at the rate of `50Hz`. Given the density of the rod is `8xx10^(3)kg//m^(3)` and specific heat is `0.11xx10^(-3)calxxkg^(@)C`. The rise in temperature per minute, if the area enclosed by the `B-H` loop corresponds to energy of `10^(-2)J` is (Assume there is no radiation losses)A. `78^(@)C`B. `88^(@)C`C. `8.1^(@)C`D. none of these |
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Answer» Correct Answer - C `50xx60xx10^(-2)=dx xx0.11xx10^(-3)xx4.2xxDeltat` |
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