1.

An iron rod of 1 cm2 cross-sectional area is placed in a magnetising field of 200 oersted. Then a magnetic field 300 G is produced. Calculate permeability and magnetic susceptibility of the rod.

Answer»

Given: Cross-sectional area A = 1 cm2
Magnetising field H = 200 oersted
Produced magnetic field B = 3000G
Permeability μ = \(\frac{B}{H}=\frac{3000}{200}\) = 15
and μ = (1 + Xm
15 = (1 + Xm)
Magnetic susceptibility Xm = 15 - 1 = 14



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