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An iron rod of length 50cm is joined at an end to copper rod of length 100 cm at 20^(0)C. Find the length of the system at 100^(0)C and average coefficient of linear expansion of the system. (alpha_(iron) = 12 xx 10^(-6)//^(0) C and alpha_("copper") = 17 xx 10^(-6)//^(0) C . ) |
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Answer» Solution :Increase in length of COMBINED ROD = increase in length of IRON rod + Increase in length of COPPER rod `(Delta l) = (Delta l )_(Fe) + (Delta l)_(Cu)` `(l_(Fe) + l_(Cu)) prop_("Avg") Delta t = l_(Fe ) prop_(Fe) Delta + l_(Cu) prop_(Cu) Delta t` `prop_("Aug") = (l_(Fe) prop_(Fe)+l_(Cu) prop_(Cu))/((l_(Fe) + l_(Cu)))` `= (50 XX 12 xx 10^(-6) + 100 xx 17 xx 10^(-6))/(150) = 15.33 xx 10^(-6) //^(0)`C |
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