1.

An iron rod of length 50cm is joined at an end to copper rod of length 100 cm at 20^(0)C. Find the length of the system at 100^(0)C and average coefficient of linear expansion of the system. (alpha_(iron) = 12 xx 10^(-6)//^(0) C and alpha_("copper") = 17 xx 10^(-6)//^(0) C . )

Answer»

Solution :Increase in length of COMBINED ROD = increase in length of IRON rod + Increase in length of COPPER rod
`(Delta l) = (Delta l )_(Fe) + (Delta l)_(Cu)`
`(l_(Fe) + l_(Cu)) prop_("Avg") Delta t = l_(Fe ) prop_(Fe) Delta + l_(Cu) prop_(Cu) Delta t`
`prop_("Aug") = (l_(Fe) prop_(Fe)+l_(Cu) prop_(Cu))/((l_(Fe) + l_(Cu)))`
`= (50 XX 12 xx 10^(-6) + 100 xx 17 xx 10^(-6))/(150) = 15.33 xx 10^(-6) //^(0)`C


Discussion

No Comment Found