An isolated particle of mass 'm' is at rest in a horizontal plane (x-y) along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4, the speed of heavier fragments is V_(0) horizontally at the instant of explosion. At an instant t_(0) later, the smaller fragment is at y = y_(0) below the point of projection. Then

An isolated particle of mass 'm' is at rest in a horizontal plane (x-y

1.	An isolated particle of mass 'm' is at rest in a horizontal plane (x-y) along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4, the speed of heavier fragments is V_(0) horizontally at the instant of explosion. At an instant t_(0) later, the smaller fragment is at y = y_(0) below the point of projection. Then
Answer» The HORIZONTAL separation between the two fragments is `3V_(0) t_(0)` at that instant `t_(0)` The horizontal separation between the two fragments is `2V_(0) t_(0)` at that instant `t_(0)` The speed of the smaller fragment at the instant `t_(0)` is `sqrt(V_(0)^(2) + 2G y_(0))` The speed of the smaller fragment at the instant `t_(0)` is `sqrt(9V_(0)^(2) + 2g y_(0))` Answer :A::D