An isolated particle of mass m is moving in horizontal plane along the x - axis at a certain height above the ground. It suddenly explodes into two fragments of masses (m)/(4) and (3m)/(4). At an instant the smaller fragment is at y=+15 cm. The larger fragment, at this instant is at.

An isolated particle of mass m is moving in horizontal plane along the

1.	An isolated particle of mass m is moving in horizontal plane along the x - axis at a certain height above the ground. It suddenly explodes into two fragments of masses (m)/(4) and (3m)/(4). At an instant the smaller fragment is at y=+15 cm. The larger fragment, at this instant is at.
Answer» Solution :As `VEC(F)_(y)=0 "" Delta vec(P)_(y)=0 " " vec(P)_(YI)=vec(P)_(YF)` `vec(P)_(yi)=0 "" therefore m_(1)vec(V)_(y_(1))+m_(2)vec(V)_(y_(2))=0, m_(1)vec(y)_(1)=-m_(2)vec(y)_(2)` `y_(2)=-((CANCEL(m))/(4)xx15)/((3cancel(m))/(4))"" y_(2)=-5 cm`.