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An isosceles glass prime ( refractive index `=(3)/(2)`) has its base just submerged in water ( refractive index `= (4)/(3)`) . The base of the prism is horizontal. A horizontal light ray AB is incident on the prism and takes a path shown in figure to emerge out of the prism. Find the maximum value of base angle `theta` of the prism for which total internal reflection can take place at the base. |
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Answer» Correct Answer - `theta_(max) = cos^(-1) (sqrt((17)/(21)))` |
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