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Find the size of the image formed in the situation shown in figure. |
Answer» Here u=-40cm, R=-20cm, `mu_1=1, mu_2=1.33. We have` `mu_2/v-mu_1/u=(mu_2-mu_1)/R` `or, 1.33/v-1/(-40cm)=1.33/(-20cm)` or, `1.33/v=-1/(40cm)-0.3./(20cm)` `or v=-32cm` The magnification is `m=h_2/h_1=(mu_1v)/(mu_2u)` `or h_2/(1.0cm)=(-32cm)/(1.33x(-40cm)` or `h_2=+0.6cm` The image is erect. |
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