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An L-shaped tube is held in a stream. It has a small orifice at the upper end which is 0.106 m above the surface of water. If water in stream is flowing at 2.45 ms^(-1) and entering at the other end of the tube, then find the height of the jet of water coming out from the orifice. |
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Answer» Solution :We know that `v_(1)^(2)-v_(2)^(2)=2/p(P_(2)-P_(1))=2/p(hrhog)=2hg` `=2 xx 0.106 xx 9.8 =2.0776=2.08` HENCE, `v_(2)^(2)=2.45^(2)-2.08^(2)` `therefore v_(2)=1.98ms^(-1)` We GET `0=(1.98)^(2)-2(1.98)H` Height to which jet REACHES will be, `h=(1.98 xx 1.98)/(19.6)=0.20m` h=20.0m |
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