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An object 30cm high is placedperpendicular to the principal axis of aconcave lens of focal length 7.5cm. Theimage is formed at a distance of sem from thelens . Find the distances which the object isplaced and the nature of the image​

Answer» <html><body><p>distance of <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a>..=<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> cm</p><p>nature of image-same <a href="https://interviewquestions.tuteehub.com/tag/size-1211196" style="font-weight:bold;" target="_blank" title="Click to know more about SIZE">SIZE</a>,same width,real and inveeted..</p><p><strong>Explanation:</strong></p><p>if the distance of object and image is same then for sure it is placed on <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> of curvature and it is the property of the lens to form image at the same position as that of object if it is placed on radius of curvature..which is </p><p>R=2f</p><p>R=2*7.5</p><p>R=15cm..</p></body></html>


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