an object 4cm in size is placed at a distance of 25cm from a concave m

1.	an object 4cm in size is placed at a distance of 25cm from a concave mirror of focal length 15 cm find the position nature and height of image
Answer» Answer: Explanation: Height of the Object(H₀) = 4 CM. Object Distance(U) = 25 cm.(negative) Focal Length = 15 cm.(negative) Using the Mirror's Formula, ⇒ ⇒ v = - 37.5 cm. Thus, the image is formed behind the mirror. Since the Distance is Negative, thus the Image is Real. Thus, Screen is to be PLACED at a Distance of 37.5 cm behind the Mirror. Now, Magnification = H₁/H₀ Also, Magnification = -v/u ∴ H₁/H₀ = -v/u ⇒ H₁/4 = - (-37.5)/25 ⇒ H₁ = 37.5 × 4/25 ⇒ H₁ = 150/25 ⇒ H₁ = 6 cm. Since, the Size of the Image is greater than the size of the Object, thus the image is Magnified.

an object 4cm in size is placed at a distance of 25cm from a concave mirror of focal length 15 cm find the position nature and height of image

Answer»

Answer:

Explanation:

Height of the Object(H₀) = 4 CM.

Object Distance(U) = 25 cm.(negative)

Focal Length = 15 cm.(negative)

Using the Mirror's Formula,

⇒

⇒ v = - 37.5 cm.

Thus, the image is formed behind the mirror. Since the Distance is Negative, thus the Image is Real.

Thus, Screen is to be PLACED at a Distance of 37.5 cm behind the Mirror.

Now, Magnification = H₁/H₀

Also, Magnification = -v/u

∴ H₁/H₀ = -v/u

⇒ H₁/4 = - (-37.5)/25

⇒ H₁ = 37.5 × 4/25

⇒ H₁ = 150/25

⇒ H₁ = 6 cm.

Since, the Size of the Image is greater than the size of the Object, thus the image is Magnified.

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