An object at an angle such that the horizontal range is 4 time of the maximum height. What is the angle of projection of the object?

An object at an angle such that the horizontal range is 4 time of the

1.	An object at an angle such that the horizontal range is 4 time of the maximum height. What is the angle of projection of the object?
Answer» SOLUTION :Horizontal range `=(u^(2)sin2theta)/(g)=(2U^(2)sinthetacostheta)/(g)` Maximum height `=(u^(2)sin^(2)theta)/(2g)` as given `(2u^(2)sinthetacostheta)/(g)=(4U^(2)sin^(2)theta)/(2g)` `2costheta=2sintheta` `tantheta=1` `:.theta=45^(@)`