An object at rest starts moving. It covers a distance of 2 m in one se

1.	An object at rest starts moving. It covers a distance of 2 m in one second. It covers a, further distance of 5 m in two seconds in the same direction what is the average velocity and acceleration?
Answer» distance traveled on 1 sec = 2 mts distance traveled on 2 sec = 5 mts total distance traveled = 2 + 5 = 7 mts total time taken to cover 7 mts = 1+2 = 3 sec \(Average =\frac {\textit{Total distance travelld}}{\textit{Total times taken}} \) = \(\frac{7}{3}\)= 2.3 ms^-1 Average velocity = 2.3 ms^-1 s = ut + \(\frac{1}{2}\) at² 7 = 0 3 +\(\frac{1}{2}\) a × 3² 7 =0 + \(\frac{1}{2}\) a × 9 = a = 7 9a =7 × 2 = 14 a =\(\frac{14}{9}\) = 1.5 ms^-2.

An object at rest starts moving. It covers a distance of 2 m in one second. It covers a, further distance of 5 m in two seconds in the same direction what is the average velocity and acceleration?

Answer»

distance traveled on 1 sec = 2 mts

distance traveled on 2 sec = 5 mts

total distance traveled = 2 + 5 = 7 mts

total time taken to cover 7 mts

= 1+2 = 3 sec

\(Average =\frac {\textit{Total distance travelld}}{\textit{Total times taken}} \)

= \(\frac{7}{3}\)= 2.3 ms^-1

Average velocity = 2.3 ms^-1

s = ut + \(\frac{1}{2}\) at²

7 = 0 3 +\(\frac{1}{2}\) a × 3²

7 =0 + \(\frac{1}{2}\) a × 9

= a = 7

9a =7 × 2 = 14

a =\(\frac{14}{9}\) = 1.5 ms^-2.