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An object falling through a fluid is observed to have acceleration given by a = g - bv where g = gravitational acceleration and b is constant. After a long time of release, it is observed to fall with constant speed. What must be the value of constant speed ? |
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Answer» Solution :When speed becomes constant acceleration `a = (dv)/(dt) =0` `a = g - bv `(GIVEN) It is CLEAR from above equation as speed increases acceleration will DECREASE. At a certain speed say `v _(0),` acceleration will be zero and speed will remain constant. `implies a = g - B v _(0)` `therefore 0 =g - bv _(0)` `therefore v _(0) = (g)/(b)` |
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