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An object falls freely from rest. It covers the same distance in last second. Which is covered in first 3 seconds, then in .............., it will reach the ground. |
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Answer» 3s `therefore` Distance covered in `n^(th)` second, `therefore In d _(n) = V _(0) + g/2 (2n -1) , v _(0) =0` `therefore d _(n) = (10)/(2) (2n -1)` `therefore d _(n) = 10 n -5 ""..(i)` and distance covered in first three seconds, `S_(3) = v _(0) t +1/2 g t ^(2) and v_(0) =0, t = 3s, g = 10 MS ^(-2)` `therefore S_(3) =0 xx 3 + 1/2 xx 10 xx 9` `therefore S_(3) = 45M""...(ii)` For given condition `d_(n) = S_(3)` `therefore 10 n - 5=45` `therefore 10n=50` `therefore n = 5s` |
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