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An object falls from a bridge which is 45m above the water. It falls directly into a small row - boat moving with constant velocity that was 12m from the point of impact when the object was released. What was the speed of the boat? |
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Answer» Solution :VELOCITY of boat = `V=(s)/(t)` Here, `s=12m` t = time of fall of OBJECT from bridge `=sqrt((2h)/(g))=sqrt((2xx45)/(10))=3s therefore V=(12)/(3)=4ms^(-1)` |
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