An object has an excess charge of `(-1.92xx10^(10-7)) C`. How many excess electrons does it have ?

An object has an excess charge of `(-1.92xx10^(10-7)) C`. How many exc

1.	An object has an excess charge of `(-1.92xx10^(10-7)) C`. How many excess electrons does it have ?
Answer» Here, excess charge `q = (-1.92xx10^(-17))C` Charge on one electron `e =(-1.6xx10^(-9)) C`. No. of excess electrons reponsible for this excess charge. `n = (q)/(e) = (1.92xx10^(-18))/(1.6xx10^(-19)) = 120` electrons

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An object has an excess charge of `(-1.92xx10^(10-7)) C`. How many excess electrons does it have ?

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