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An object has velocity `vec v = (i+2hatj+3hatk)m//s`. A constant acceleration of the object for which its speed starts decreasing is:A. `vec a= 2hatj+hatk`B. `veca = 7hati-6hatj-hatk`C. `veca = 7hati+hatj-hatk`D. `veca = 3hati-4hatj+2hatk` |
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Answer» Correct Answer - B An object …………… speed starts decreasing of `veca. vecv lt 0` |
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