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An object is 30.0 cm from a spherical mirror along the central axis. The absolute value of lateral magnification is `(1)/(2)`. The image produced is inverted. What is the focal length of the mirror? |
Answer» Image is inverted, so it is real, u and v both are negative. Magnification is `(1)/(2)`,therefore,v=`(u)/(2)`. Given, u=-30cm and v=-15 cm Using the mirror formula, `(1)/(v)+(1)/(u)=(1)/(f)` we have, `(1)/(f)=(1)/(-15)-(1)/(30)=(1)/(10)` `therefore` Focal length f=-10 cm |
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