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An object is 40 cm form a spherical mirror, along the central axis. The image produced is inverted. What is the power of the mirror?

Answer» Image is inverted, so it is real, u and v both are negative.
Magnification is `(1)/(2)`,therefore,v=`(u)/(2)`.
Given, u=-40cm and v=-20 cm
Using the mirror formula, `(1)/(v)+(1)/(u)=(1)/(f)`
we have, `(1)/(f)=(1)/(-20)-(1)/(40)=(-2-1)/40=(-3)/40`
`rArr f=-40/3cm=-40/3xx1/100m=-2/15m`
`therefore` Power of the mirror, `P=-1/f=(-1)/(-2/15)=15/2=+7.5 D`


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