An object is allowed to fall freely from a cliff. When it travels a distance 'h', its velocity is v. Hence, in travelling further distance of ........ its velocity will become 2v.

An object is allowed to fall freely from a cliff. When it travels a di

1.	An object is allowed to fall freely from a cliff. When it travels a distance 'h', its velocity is v. Hence, in travelling further distance of ........ its velocity will become 2v.
Answer» 4h 3h 2h h Solution : Equation for freely falling BODY, `v ^(2) -v _(0)^(2) =2gd` Here initial velocity `v _(0) = 0 and d =h` `THEREFORE v ^(2) =2gh` ` therefore h = (v ^(2))/(2g) ""…(1)` The velocity of an object at height h is `v _(0) = vand ` the velocity of an object at height h. will be 2v. `therefore (2v)^(2) -v ^(2) =2gh.` `therefore 4v ^(2) -v ^(2) = 2gh.` `therefore 3v ^(2) =2gh.` `therefore h . = (3v ^(2))/( 2g) ""...(2)` `therefore (h.)/(h) =3` [Taking the RATIO of equ. (2) and equ. (1)] `therefore h. =3h`