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An object is attched to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is `15cm//s` and the period is `628` milli seconds. The amplitude of the motion in centimetres isA. `3.0`B. `2.0`C. `1.5`D. `1.0` |
Answer» Correct Answer - C `v_(m)=15cm//s, T=6.28xx10^(-1)s` `v_(m)=Aomega` `A=(v_(m))/(omega)=(15)/(2pi)xxT` `=(15xx6.28xx10^(-1))/(6.28)=15xx10^(-1)=1.5cm`. |
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