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An object is executing uniform circular motion with an angular speed \(\frac{π}{12}\) of radian per second. At t = 0 the object starts at angle θ = 0. What is the angular displacement of the particle after 4 s? |
Answer» Given: Angular speed = \(\frac{π}{12}\)rad/ sec Angular speed = \(\frac{angular\, displacement}{time \, taken}\) Angular displacement = \(\frac{π}{12}\) x 4 = \(\frac{π}{12}\) = 60° |
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