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An object is kept on the principal axis of a concave mirror of focal length 12 cm. If the object is at a distance of 18 cm from the mirror, calculate then image distance. Determine the nature of the image formed by calculatingthe magnification produced by the mirror, |
Answer» Given :-
To FIND :-
Solution :-Apply mirror formula → 1/v + 1/u = 1/f → 1/v + (-1)/18 = -1/12 → 1/v = 1/18 - 1/12 → 1/v = 2 - 3/36 → 1/v = -1/36 → v = - 36cm Hence,
★ Magnification of mirror ★ → m = -v/u = hi/ho → m = -v/u → m = -(-36)/-18 → m = -36/18 → m = - 2 Hence,
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