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An object is placed `10cm` away form a glass piecwe `(n = 1.5)` of length `20cm` bounded by spherical surfaces of radii of curvaure `10cm`. Find the position of final image formed after two refractions at the spherical surfaces. |
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Answer» Correct Answer - `50cm` right of `B` For first reaction: `(1.5)/(v_(1)) - (1)/(-10) = (1.5-1)/(10) rARr v_(1) = -30cm` For secound refractions `u = -(30+20) = -50cm` `:. (1)/(v_(2)) - (1.5)/(-50) = (1-1.5)/(-10)` `rArr v_(2) = 50cm` Hence, final image is formed `50cm` right of `B`. |
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