1.

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

Answer»

Given: f = 15

u = -10

From mirror formula, \(\frac{1}{u} + \frac{1}{v} = \frac{1}{f}\)

\(\frac{1}{-10} + \frac{1}{v} = \frac{1}{15}\)

v = 6 cm

Image is formed 6 cm to the right of the mirror. Image formed is virtual and erect.



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