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An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image. |
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Answer» Given: f = 15 u = -10 From mirror formula, \(\frac{1}{u} + \frac{1}{v} = \frac{1}{f}\) = \(\frac{1}{-10} + \frac{1}{v} = \frac{1}{15}\) v = 6 cm Image is formed 6 cm to the right of the mirror. Image formed is virtual and erect. |
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