1.

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image. 

Answer»

Given f =  +15 cm, u = – 10 cm, v = ?

By mirror formula

1/v + 1/10 = 1/15 …. (i)

Put the given values in eq. (i) with their sign conventions 

1/v - 1/10 = 15

We get, v = 6 cm

image is formed at 6 cm away from the mirror on right side i.e. virtual

m = –v/u  =  –6/-10  = 0.6

Here, m is less than unity and also positive so image will be diminished, erect and virtual in nature. 



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