An object is projected with a velocity of 20 m/s making an angle of 45∘ with horizontal. The equation for the trajectory is h=Ax−Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B has value of (g=10 ms−2)

An object is projected with a velocity of 20 m/s making an angle of 45

1.	An object is projected with a velocity of 20 m/s making an angle of 45∘ with horizontal. The equation for the trajectory is h=Ax−Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B has value of (g=10 ms−2)
Answer» An object is projected with a velocity of $20 m/s$ making an angle of $45^{\circ}$ with horizontal. The equation for the trajectory is $h = A x - B x^{2}$ where $h$ is height, $x$ is horizontal distance, A and B are constants. The ratio A : B has value of $(g = 10 m s^{- 2})$

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An object is projected with a velocity of 20 m/s making an angle of 45∘ with horizontal. The equation for the trajectory is h=Ax−Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B has value of (g=10 ms−2)

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