InterviewSolution
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InterviewSolution
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An object is thrown along a direction inclined at an angle of `45^(@)` with the horizontal direction. The horizontal range of the particle is equal toA. vertical heightB. twice the vertical heightC. thrice the vertice heightD. four times the vertical height |
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Answer» Correct Answer - D `(R)/(H) = ((u^(2)sin 2theta)/(g))/((u^(2)sin^(2)theta)/(2g)) = (2sin theta cos theta)/(g) xx (2g)/(sin^(2)theta) = 4 cot theta` `rArr R = 4H cot theta` if `theta = 45^(@)` then `R = 4H cot (45^(@)) = 4H` |
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