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An object is thrown to a certain height with a velocity of 3 m/s. If the time required to reach the height is 5s. Calculate the height at which it was thrown. [Hint: (g=10m/s^2) (use second equation of motion)]

Answer» EACHES the ground It's displacement is 0 A =-10m/s^22 U=100m/s S=ut+1/2at^2 0=100t-5t^2 5t^2=100t 5t=100 t=100/5 t=20s The BALL will REACH the ground in 20s Hope this HELPS: Thank you.


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